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http://users.zoominternet.net/~matto/Java/Moon's%20Position.htm

Calculating the Moon's Position

by Matt Oltersdorf 2003 10 26 14:55 UTC
back to Java for Astronomy



WRITE DATE AND U.T. HOUR:
Day:  Month:  Year:  Hour:  Minutes:   

Julian Day:       Parallax  ('):  
Moon Longitude:     Moon Latitude: 
Right Ascension:  =  h  m  s  
Declination:      =    '  "


  
 
Quote:
Originally Posted by LukeS View Post
I imagine that the disparity is so minutely different for objects 1000m and 2000m away that a shaky finger and a cross eyed measurement will not accurately bring out the real distance/disparity, and generally as the curve flattens off as we measure and collate the splitting for objects further and further away, it will be increasingly difficult to calculate and measure differences.
Yep, a quick calculation (using angle rather than distance, because it's easier) gives a value of 0.463597 at 1000m, 0.463622 at 2000m. That's a relative difference of about 0.0054 percent. The moon turns out to be 0.463647, another 0.0054 percent away from them by some strange coincidence.

(The formula for the angle I got was where d is the distance to the object, c is the distance to finger ("calibration") and e is the distance between your nose and an eye. I assumed c was 0.1 and e 0.05).

Edit: Here's a graph of the angle against distance (in metres):


Quote:
But in principle the method should work, shouldn't it?
Yep, it's called parallax and we do use it to measure nearby stellar objects (albeit the "eyes" are the Earth on opposite points of its orbit around the sun).
 
 

Cece Stevens 2001

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